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{"id":2739,"date":"2018-10-14T16:20:03","date_gmt":"2018-10-14T23:20:03","guid":{"rendered":"https:\/\/www.waterandwastewatercourses.com\/?p=2739"},"modified":"2020-02-12T17:45:31","modified_gmt":"2020-02-13T01:45:31","slug":"water-math","status":"publish","type":"post","link":"https:\/\/www.waterandwastewatercourses.com\/water-math\/","title":{"rendered":"Water Math Practice Problem – Chlorination"},"content":{"rendered":"\t\t
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Here’s an important water math practice problem.  First, try to solve it without looking at the answer.  If you don’t know how to solve it, read the following step-by-step solutions carefully until you understand it.  Moreover, you may want to enroll in this online water math course<\/a>, if you need help.  <\/span><\/p>\n

Above all, take your time, and don’t rush through it.  Certainly, the most important thing is to learn how to solve this type of math problem before you take the operator certification test.      <\/span><\/p>\n

  <\/span><\/p>\n

PRACTICE QUESTION<\/span><\/strong><\/span><\/h2>\n

How many gallons of 12.5% sodium hypochlorite solution are required each day to disinfect a water supply flowing at a rate of 1.5 MGD, if the desired chlorine dose is 2.5 mg\/L?  <\/span>The specific weight of 12.5% sodium hypochlorite solution is 10.2 lbs\/gallon.<\/span><\/p>\n

  <\/span><\/p>\n

\"water<\/a><\/p>\n

 <\/span><\/p>\n

ANSWER<\/span><\/strong><\/span><\/h2>\n

Step 1:  LIST ALL THE DATA GIVEN<\/span><\/strong><\/span><\/h2>\n


<\/span><\/strong><\/span><\/p>

KNOWN<\/span><\/strong>                                                                                  <\/span><\/p>\n

Flowrate = 1.5 MGD                                                               <\/span><\/p>\n

Chlorine dose = 2.5 mg\/L<\/span><\/p>\n

Specific weight of 12.5% sodium hypochlorite = 10.2 lbs\/gallon<\/span><\/p>\n

 <\/span><\/p>

UNKNOWN<\/strong><\/span><\/span><\/p>\n

Gallons\/day of solution<\/span><\/p>\n

  <\/span><\/p>\n


<\/span><\/strong><\/span><\/h2>

Step 2:  CALCULATE LBS\/DAY OF PURE CHLORINE REQUIRED<\/span><\/strong><\/span><\/h2>\n


<\/span><\/span><\/p>

lbs \/ day = (Flowrate, MGD) x (Dose, mg\/L) x (8.34 lbs\/gallon)<\/span><\/span><\/p>\n


<\/span><\/em><\/p>

\u2666First, enter the flowrate in MGD, and chlorine dose in mg\/L.<\/span><\/em><\/p>\n


<\/span><\/p>

lbs \/ day = (1.5 MGD) x (2.5 mg\/L) x (8.34 lbs\/gallon)<\/span><\/p>\n

= 31.28 lbs\/day of pure chlorine<\/span><\/p>\n


<\/span><\/em><\/p>

\u2666This is the lbs\/day of pure chlorine required.<\/span><\/em><\/p>\n

\u2666However, we’re not using pure chlorine to disinfect the water.  Instead, we’re using 12.5% sodium hypochlorite solution, which is weaker than pure chlorine.  In fact, the strength of 12.5% sodium hypochlorite solution is only 12.5% of pure chlorine.<\/span><\/em><\/p>\n

\u2666 Therefore, in STEP 3<\/strong>, we have to convert lbs\/day of pure chlorine from STEP 2<\/strong> to lbs\/day of 12.5% sodium hypochlorite.<\/span><\/em><\/p>\n

  <\/span><\/p>


<\/span><\/p>\n

Step 3:  CALCULATE LBS\/DAY OF 12.5% SODIUM HYPOCHLORITE REQUIRED<\/span><\/strong><\/span><\/h2>\n


<\/span><\/em><\/p>

\u2666Since the strength of 12.5% sodium hypochlorite solution is only 12.5% of pure chlorine, we have to divide the lbs\/day of pure chlorine from STEP 2<\/strong> by .125, which is the decimal format of 12.5%.<\/span><\/em><\/p>\n

\u2666Therefore, use “31.28<\/span> <\/span>lbs\/day of pure chlorine” from STEP 2<\/strong>, and divide it by .125.  Consequently, this will give us the lbs\/day of 12.5% sodium hypochlorite required.<\/span><\/em><\/p>\n


<\/span><\/p>

 <\/span><\/p>\n

\"\"<\/a> <\/span><\/p>\n

 <\/span><\/p>\n

\u2666Next, we have to convert 250.2 lbs\/day to gallons\/day, since the problem statement wants the answer in gallons\/day.<\/span><\/em><\/p>\n

 <\/span><\/strong><\/span><\/h2>\n

Step 4:  CALCULATE GALLONS\/DAY OF 12.5% SODIUM HYPOCHLORITE REQUIRED<\/span><\/strong><\/span><\/h2>\n


<\/span><\/em><\/p>

\u2666Use “250.2 l<\/span>bs\/day of 12.5% sodium hypochlorite” from STEP 3<\/strong>, and divide it by the specific weight of 12.5% sodium hypochlorite, which is 10.2 lbs\/gallon.  The specific weight tells you how many pounds each gallon of the chemical weighs.  To point out, this number was given to us in the problem statement.  Using the specific weight, we can convert lbs\/day to gallons\/day, as shown below.<\/span><\/em><\/p>


<\/span><\/em><\/p>\n

<\/p>\n

\"\"<\/a> <\/span><\/p>\n

\n<\/p>

Therefore, the answer is 24.5 gallons\/day.<\/span><\/p>\n


<\/span><\/strong><\/h2>

CONCLUSION<\/span><\/strong><\/h2>\n

If this was your first time solving this type of water math question, it was probably a bit challenging.  However, if you practice solving a lot of these water math questions, you’ll be able to master it.  <\/span><\/p>\n

Moreover, one of the best ways to improve your overall math skills is to solve many water math problems.  Hence, repetition is the key to success. <\/span><\/p>\n

Lastly, it’s also important to solve relevant water math questions.  They have to be similar to the ones tested on the operator certification test.    <\/span><\/p>\n

HELPFUL RESOURCES<\/span><\/strong><\/h2>\n

Practice Tests with Water Math Questions<\/span><\/a><\/h2>\n

Online Water Math Course<\/span><\/a><\/h2>\n

Finally, if you’re looking for more practice problems, click here.<\/a><\/span><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t\t\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t","protected":false},"excerpt":{"rendered":"

Here’s an important water math practice problem.  First, try to solve it without looking at the answer.  If you don’t know how to solve it, read the following step-by-step solutions carefully until you understand it.  Moreover, you may want to enroll in this online water math course, if you need help.   Above all, take your …<\/p>\n

Water Math Practice Problem – Chlorination<\/span> Read More \u00bb<\/a><\/p>\n","protected":false},"author":1,"featured_media":2927,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0},"categories":[109,111,101],"tags":[],"jetpack_featured_media_url":"https:\/\/www.waterandwastewatercourses.com\/wp-content\/uploads\/2018\/10\/clem-onojeghuo-33741-unsplash.jpg","_links":{"self":[{"href":"https:\/\/www.waterandwastewatercourses.com\/wp-json\/wp\/v2\/posts\/2739"}],"collection":[{"href":"https:\/\/www.waterandwastewatercourses.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.waterandwastewatercourses.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.waterandwastewatercourses.com\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.waterandwastewatercourses.com\/wp-json\/wp\/v2\/comments?post=2739"}],"version-history":[{"count":133,"href":"https:\/\/www.waterandwastewatercourses.com\/wp-json\/wp\/v2\/posts\/2739\/revisions"}],"predecessor-version":[{"id":3775,"href":"https:\/\/www.waterandwastewatercourses.com\/wp-json\/wp\/v2\/posts\/2739\/revisions\/3775"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.waterandwastewatercourses.com\/wp-json\/wp\/v2\/media\/2927"}],"wp:attachment":[{"href":"https:\/\/www.waterandwastewatercourses.com\/wp-json\/wp\/v2\/media?parent=2739"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.waterandwastewatercourses.com\/wp-json\/wp\/v2\/categories?post=2739"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.waterandwastewatercourses.com\/wp-json\/wp\/v2\/tags?post=2739"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}